{"id":1611,"date":"2024-04-16T07:06:02","date_gmt":"2024-04-16T01:36:02","guid":{"rendered":"http:\/\/codetheory.in\/?p=1611---2121a2b6-4375-4465-929e-cae49d719ac3"},"modified":"2024-04-16T07:06:02","modified_gmt":"2024-04-16T01:36:02","slug":"why-clearrect-might-not-be-clearing-canvas-pixels","status":"publish","type":"post","link":"https:\/\/codetheory.in\/why-clearrect-might-not-be-clearing-canvas-pixels\/","title":{"rendered":"Why clearRect Might Not be Clearing the Canvas Pixels"},"content":{"rendered":"
Sometimes the <\/p>\n The solution to this problem is actually quite simple but the issue itself can cause major headache if you’re unable to nail it. We basically have to call the The stacking up of all the previous path drawing functions due to not closing the paths (with <\/p>\nclearRect(x, y, width, height)<\/code> method on the canvas context might not erase the previous graphics drawn. This usually happens when we’re drawing paths using methods like
lineTo()<\/code>,
arc()<\/code>,
rect()<\/code>, etc. and then stroking them with
stroke()<\/code> or filling their content area using
fill()<\/code>. Here’s<\/a> an example of what I’m trying to convey.<\/p>\n
beginPath()<\/code> method on the 2D context. This method will create a new path and all the drawing functions called later will be directed to it. If we do not call
beginPath()<\/code> (and then preferably closing that using
closePath()<\/code>), then all the drawing commands called will stack up in the memory and every time
stroke()<\/code> or
fill()<\/code> is called, it’ll draw all the graphic paths.<\/p>\n
beginPath()<\/code> and
closePath()<\/code>) and hence not getting cleared (with
clearRect()<\/code>) can lead to unpleasant results in animations. Here’s an image of what you can expect for a
rect()<\/code> call with
stroke()<\/code> in such a situation.<\/p>\n